The fact is, if you connect a 8 ohm resistor to a 16 V source, the current flow will be 2 A whether you measure it upstream or downstream of the resistor load. Same for a filter load such as a series inductor, the current will be the same at the input and output side of the filter.
Unlike something like a mechanical filter (eg paper cone) the electrical filter load (LCR network for passive) enforces the filtered effect/frequency spectrum of the signal right at the connection point at source, ie in this case the amp’s output terminals. If you measure/probe for voltage then yes you won’t see the filtered effect, it will be full bandwidth for both pairs of wires, biwire or not. In that case the current seen by the instrument will be subjected to the very high input impedance of the instrument so any connected filter loads will have insignificant effects.
As you alluded to, I suppose, in the last video, that sometimes there may not be mechanical analogy that fits perfectly to electrical circuit theories.