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pam : Hi
I get the part about W=VxA. I also get the 55% of A/B amplifier class.
Now, if I use a 8 ohm speaker and I get 100 Watt and with a 4 ohm speaker then I will get more watts (let say 165 Watt).
If we have 55% efficiency with 100 Watts in 8 ohm. Then the total Power used is about 181 Watts. Getting 165 watts in 4 ohm would means 91% efficiency.
This would also mean that their is less heat with 4 ohm speakers than with 8 ohm.
Thanks
IF, an amplifier is capable of running a 4 ohm load, it may or may not give you more power into the 4 ohm load. It depends on the amplifier design. If it is a regulated design, it may actually output the same amount of power into 4 ohms as 8 ohms. Some (really well made) amplifiers will double their output as you decrease the resistance (8 ohms to 4 ohms, 4 ohms to 2 ohms). MOST receivers do NOT follow the latter description. However, in any case, this CANNOT improve the efficeny of the amplifier class. Remember that power flows more freely into lower impedences. Also, remember that the wattage (and or current) draw from the wall, on almost all receivers and amplifiers is tested with an 8 ohm load on the channels. By putting a 4 ohm load on an amplifier, it will draw more from the wall if the design allows (being it will double it's power into half the impedence). Power output is a product of current drawn times the efficency. The amount of current drawn is in direct correlation with the output of the amplifier minus wasted power (efficency, power to run displays, ect.).
In your equation above, if an amplifier were capable of 100 watts rms power at 8 ohms all (7) channels driven simultaneously, the receiver would draw from the wall, roughly, in the neighborhood of 1,273 watts of power or 10.6 amperes.
To figure this out we take 100 watts x 7= 700 watts divided by amplifier (class A/B) efficency average of 55% we get 1272.72 watts. To find amperage simply divide by 120 = 10.6 amperes. Now, IF that amplifier were capable of nearly doubling it's power (roughly 2/3's more) to 165 watts into 4 ohms x 7 simultaneously the wattage draw would increase to about 2100 watts (17.5 amperes) of current draw.
We arrive at these numbers by the following:
165 x 7= 1,155 watts
1,155 watts divided by .55 (55% efficency class A/B) = 2,100 watts
2,100 watts divided by 120 volts = 17.5 amperes
If a receiver or amplifier were capable of this kind of power, it would require it's OWN 20 AMPERE CIRCUIT!!
As far as heat goes, heat increases as the impedence drops as the aplifiers devices have to work somewhat harder into the lower impedence. If a receiver or amplifier were truly capable of the above, there would most likely not be a large difference in heat. If you were to go to 2 ohms, there would be a definite increase.</font>