Dayton 18" HO Ported Build Thread

1

1Randy

Audioholic Intern
To calculate the volume of a cone, use the formula: volume = (1/3) × π × r² × h, where r is the radius of the base and h is the height of the cone. Simply plug in the values for r and h to find the volume.

You'll need to subrtact the small volume where the voice coil attaches for total accuracy, but it's negligible.
Volume Displacement = Sd x Xmax

Example:

So (1) ultimax 18" = more than (3) RSS315HF
 
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H

highfigh

Seriously, I have no life.
Volume Displacement = Sd x Xmax

Example:

So (1) ultimax 18" = more than (3) RSS315HF
Ever try to model an enclosure without a full set of Theil-Small parameters? If Sd isn't included, you'll need to calculate the area and I posted a tool that can be used by anyone, not just you.
 
1

1Randy

Audioholic Intern
Ok, im just trying to figure out bass impact in a home theater, if you're using smaller drivers, how many do you need to equal bigger driver.
 
Verdinut

Verdinut

Audioholic Spartan
If the diameter is equal between the two, the deeper cone will displace more air but I never claimed a deeper cone will move more air, I provided the formula in order to show how to calculate the displacement. It's the diameter AND excursion that determine the air movement.
I have to disagree with you on that. I have Vance Dickason's Loudspeaker Design Cookbook 7th edition, and other books by Alden and Weems, and nowhere is a mention relating to a driver cone volume as a factor for air displacement.
 
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H

highfigh

Seriously, I have no life.
Ok, im just trying to figure out bass impact in a home theater, if you're using smaller drivers, how many do you need to equal bigger driver.
If you want to find the equivalent surface area with smaller drivers, divide the Sd of the larger cone by the smaller- the result may be equal (by chance), but you'll have an idea of the number of drivers to use.
 
H

highfigh

Seriously, I have no life.
I have to disagree with you on that. I have Vance Dickason's Loudspeaker Design Cookbook 7th edition, and other books by Alden and Weems, and nowhere is a mention relating to a driver cone volume as a factor for air displacement.
By the way, a deeper speaker cone does not inherently move more air than a shallower one. It's the diameter of the come that is the major factor for low frequency reproduction.

Larger cone displacement (XMax parameter) is usually inherently related with a larger cone driver.
You're right- I edited my post.
 
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