This part is correct, who is arguing?? Now, Q=CV, Q is the charge in Coulomb, C is the capacitance in Farad. It should be clear from this formula that the "Charge held.." is proportional to C (unit in mfd) and the applied voltage (unit in V, i.e. volt).
No, are you mixing up "Charge" with "Capacitance" ? You don't store mfd, you store Coulombs, higher mfd value means more Coulombs you can store, at a given applied voltage.
Incorrect ! As mentioned above, you don't store 25 mfd, 25 mfd is microfarad, or uF, that is the capacitance, and is equal to Q/V. So you can see clearly that since Q=CV, so as you said, the charge is proportional to voltage, but it is also proportional to the capacitance.
If the applied voltage is the same, then the charge held in the example you are using will be the same, as shown below.
In your example of 25 mfd, charged to 50 volts:
Q=CV = 25 X 10−6 X 50 = 0.00125 Coulomb.
That is so incorrect! TLS Guy, I know and do respect your knowledge. I called you out before (rarely) on certain things, usually on the power and electronic side, and you never had problem with it. For that you have my respect too. This is about electrical principles, definitions, theories etc., so it is a matter of facts, not opinions. I hope you will do your research properly, admit the error and move on, so it won't stay on record that may mislead people inadvertently.