Okay using your analogy here I read that the Dentons are actually 5.6 ohm overall. Using the 10v rail you gave that would equal 1.79 amps. Where or shall I say why did you mention the 10v? Just using it as an example? Okay so 1.79 amps at 10v. What does that actually mean? How would I apply that info? What can I discern from it? Thanks!
Cheers,
Phil
The impedance overall means nothing. It is the impedance in the power range that matters especially below BSC.
It really is not difficult. Lets take a 20 volt rail voltage. If the impedance is 10 ohms then the maximum current that could be delivered is 2 amps. In practice it would be a little less, but lets ignore that. So the power delivered would be 40 watts. Now lets assume we have a good linear SS amp. Now lets make the speaker impedance 5 ohms. So the current will up to 4 amps and the power to 80 watts. If it is a really linear amp dropping the impedance to 2.5 ohms will be 8 amps, and the power 160 watts. If it can't deliver the current for the power required by the input then there will be clipping. In practice an real world amps are not that linear, and the power into 2.5 ohms will probably be closer to 120 watts.
Now lets make the impedance 20 ohms. In an SS amp it can't deliver a higher voltage than the rail. So voltage clipping will occur at above 20 watts.
Now lets take a tube amp. We can get any voltage we want, by selecting an appropriate secondary tap on the output transformer. So we can match power to any impedance and have the power constant through any range of impedance as long as it is constant with frequency
However here is the rub. Few loudspeakers have constant impedance. So if we match a tube amp to the mean impedance of say 8 ohms, and say it delivers 20 watts max into the load. Lets see what happens in a real world load. If the impedance is 4 ohms at 200 Hz it will deliver 10 watts at that frequency. Now say the impedance is 6 ohms at 900 Hz, it will deliver 15 watts at that frequency. So this is how at max power at the clipping point a tube amps response starts to follow the impedance curve. So if you have a tube amp speaker selection has a huge impact on the sound you get. The reason being is that tubes can not increase current as load impedance is reduced, like SS amps can.
Now you can see why highly sensitive speakers with very simple, and especially no crossovers, are so popular in the tube community. Back in the tube days I used pretty much exclusively full range drivers with no crossover.
Lastly your quest to look at high current versus high power is just nonsensical. The two are the same side of the coin. A high powered amp is high current. A high current amp is high powered.
A low current amp that was high powered would need a high output voltage and a very high impedance load. That situation is not encountered in real world loudspeakers.
You see power is Voltage X Current, always, no exceptions. So at a given voltage then you can only increase power by dropping load impedance so current can rise.
This is really simple very basic stuff about which there can be no argument. Don't get confused by the ignorant pig dribblers wasting ink in the Audiophool press. These people are unfortunately too numerous to count, and make the Internet full of error, which is inexcusable since this matter is so simple.