<font color='#000000'>John;
I apologize, but when I check my AH email address from an outside server, I cannot retain my address book for some reason. Please email me again at:
gds@audioholics.com.
I have good feedback to share from Henry Ott and he has authorized me to reprint it.
BTW> To quote Henrys book, p149 "The internal inductance is further reduced when high frequency currents are considered since, due to skin effect, the current is concentrated near the surface of the conductor."
Skin effect doesn't cause self inductance change directly. Self inductance and internal inductance are two different things. Internal inductance is independent of wire size, thus that kills the notion of skin causing it.
Also, consider 12AWG wire, the skin depth is larger than the cross sectional area for frequencies below 5kHz. Thus below 5kHz there is absolutely no Skin Effect, yet there is still internal inductance. Internal inductance eventually gets minimized as a result of skin effect at high frequencies. Lets discuss further off line and I may turn it into another featured article.
OK John, Here is a Quick Update I worked on. Tell me if I messed up any of my reasoning:
Calculating Inductance of Twin Feeder Cables
Let me make some definitions applicable to twin feeder cables with two adjacent conductors #1 and #2:
Self Inductance: is comprised of internal and external inductance (L11 = Le1 + Li1, L22 = Le2 + Li2)
Mutual Inductance: is a result of L1 and L2 interaction (L12) where L12 < Le2, and L2 and L1 interaction (L21) where L21 < Le1. (Is there a way to calculate coupling coefficient here? IE. In PSPICE I can model two inductors with K-Linear and enter coupling coefficient)
Total Inductance: Is the sum of Self Inductance and Mutual Inductance where:
Ltot1 = L11 – L12 and Ltot2 = L22 – L21
(The negative sign of the terms L12 and L21, represent current flows in opposite direction of the other conductors L22 and L11, respectively.)
Total Loop Inductance is the sum of Ltot1 and Ltot2 where:
LTOT = Ltot1 + Ltot2 = L11 – L12 + L22 – L21
At Low to Mid Frequencies:
LTOT = .281*Log(B/A) + Li1 + Li2 where B is the space between two conductors and A is the Radius of each conductor. For very closely spaced conductors, the internal inductance terms may become important.
At High Frequencies:
Skin effect forces current to surface of conductors, thus internal inductance becomes negligible and Self Inductance becomes equal to External Inductance:
LTOT = Le1 –L12 + Le2 – L21 = .281*Log(B/A)
Summary:
At low to mid frequencies, both internal and external inductance may have to be considered. As frequency increases, skin effect causes the internal inductance to become negligible, since the current is forced to the surface of the conductors. The theory behind negligible inductance at high frequencies is, as you previously stated,
<table border="0" align="center" width="95%" cellpadding="0" cellspacing="0"><tr><td>
Quote </td></tr><tr><td id="QUOTE">"Within a wire carrying DC, there is a uniform current density profile. The magnetic flux within the wire is zero at the geometric center, and increases linearly in value as you move towards the surface of the wire...Outside the wire, the field drops off as 1/R....When a conductor is skinning heavily, as in RF, all the current has
moved to the outside surface of the conductor. From the field equations, the field within an infinitely thin cylindrical sheet of current is zero....So, at infinite frequency, the internal portion of the wire has no field, hence, no energy stored, and no inductance....That is how the skin effect alters the
internal</b> inductance of the wire."</td></tr></table>
[added more info on inductance, made corrections to thoery and conclusions]</font>