Hi, MDS,
MDS said:
The first thing to understand is that a receiver/amp is not designed or spec'ed to produce any particular output level. The output SPL you can achieve in your room depends on a lot of factors to which you have alluded: room size and acoustics, power available, speaker sensitivity, distance from the speakers to the listening position, etc.
OK, I understand. Given the variables, an amp company can only design maximum power into its products, not SPL in the end-user's environment.
MDS said:
Yes. More sensitive speakers require less power to reach the same output SPL. Doubling the power gives you a +3 dB increase in SPL. Therefore, if you can reach 105 dB SPL using 100 wpc with 90 dB sensitive speakers, you could achieve the same level with 93 dB sensitive speakers using only 50 wpc.
Good, that makes sense.
MDS said:
The 0 dB volume setting is NOT the maximum on most receivers. If the scale is -80 dB to +20 dB, then 0 dB is somewhere around 80% of maximum. That means the receiver will be using roughly 80% of its available rail voltage [I'll save that explanation for later if you are interested]. There is plenty of headroom left between 0 and the maximum but of course as you get closer to the maximum distortion and noise increase.
Sure, I understand that any scale would work, as you said in your first reply. I chose -99 dB to 0 dB here because that's what my receiver has and it's what I referred to when I started the thread.
MDS said:
Using a more powerful amp would increase the maximum possible sound level but remember - double the power equals a 3 dB increase (10*Log(100/50)= 3.01 dB). That is noticeable but not exactly a huge difference.
I understand this, I think, and I realize that the dB scale is logarithmic. Let me test myself, and see if I really understand.
Let's assume an amp of 100 watts per channel, designed and measured accurately. It drives an 8-ohm speaker of average sensitivity--let's say 87 dB/w/m. When the amp sends one watt of power to the speaker, the speaker will produce an SPL of 87 dB when measured 1 meter from the speaker's front. (I've learned that there's a little bit of resistance in the system from the wire going from the amp to the speaker, but if the wire is of sufficient thickness, let's assume that this resistance is too small to affect this discussion.)
I learned recently that sound drops off 6 dB with every doubling of distance. (Though I don't understand why sound doesn't follow the inverse-square law.) So if my listening position is 4 meters from the speaker, I've lost 12 dB of sound: 87 - 6 (at 2 meters) = 81 dB, and 81 - 6 (at 4 meters) = 75 dB.
At this point the amp is still sending 1 watt of power. So to get back to 87 dB, I need the amp to add enough power to increase the SPL by 12 dB. It would work like this
1 w = 75 dB/4 m
2 w = 78 db/4 m
4 w = 81 db/4 m
8 w = 84 dB/4 m
16 w = 87 dB/4 m
Or thinking of it another way, for every 10 dB increase in SPL, I need an order of magnitude in power increase from the amp, assuming the same conditions:
1 w = 75 dB
10 w = 85 dB
100 w = 95 dB
On top of that, I can use the amp's volume scale to tell me approximately what percentage of the amp's power I'm using, depending where I am on the scale. Do I have all this right?
Chris
P.S. OK, feel free to hit me with your available rail voltage now.