done

[gaby95]

seriously why are there so many Ted Mosbys on this forum?
I am done with asking anything around here. Gene has such a great channel and information so it is a shame to find so many Teds here.

 

[gaby95]

At 10' and 15 degrees off axis, you can probably just use the on-axis response for your guestimation purposes.

What speaker is it? Has James or Erin or Amir done any measurements on it to know what it's overall power response and expected room response are? Such data would give you more insight than a wild eyed guess about how much it changes off axis.

That is the idea to get the angles from people that are measuring them like Erin not to do "wild eyed guesses"

 

[slipperybidness]

Hi all,
I was not sure where to post this so here we go.

Point A is where my Center speaker is.
Point B is where I am sitting (in this case 10')
The angle (15º on this example) is the off-axis coverage of the center speaker.

What I am looking is for a calculator that lets me figure out how much total coverage of the audio I will get (C) as the angle varies and also as the distance from A to B varies.
Hope that makes sense.

Basically some speakers have bad off-axis response so say anything 15º off center, the audio is going to change for the listener so I want to be able to predict how this may affect or not affect a person since of course, it will vary depending on how far they are seating from A.
Thanks!

I was thinking entering angle A and side b on this calculator will give me the right answer?

Trigonometry Calculator

www.carbidedepot.com

So if I am doing it right, at 10' from a speaker with 15º off-axis response I get about 2.6' of "safe zone"...that seems to narrow so maybe I am wrong.

You really need to learn how to do any calcs manually before you use any online calculators, that way when your online results seem wonky, it is abundantly clear.

In this case, you calculated the length of B using the online calc. You need to multiply that value by 2 to get your length of C (about 5 feet).

The proper equations is

Tangent(15deg) = B/10
Therefore, B =2.67'
Therefore C = 5.4'

 

[slipperybidness]

seriously why are there so many Ted Mosbys on this forum?
I am done with asking anything around here. Gene has such a great channel and information so it is a shame to find so many Teds here.

Dunno why you are suddenly butt hurt. I clearly answered your questions and tried to educate you on the topic, your original post is captured and documented on my reply on post #4, then you come back and change your OP to some non-sense.

 

[TLS Guy]

seriously why are there so many Ted Mosbys on this forum?
I am done with asking anything around here. Gene has such a great channel and information so it is a shame to find so many Teds here.

Who in the Hell is Ted Mosby? Never heard of the geezer.

 

[shadyJ]

Who in the Hell is Ted Mosby? Never heard of the geezer.

According to Google, Ted Mosby is a character from a sitcom called "How I met Your Mother." Not so surprising to see such an obscure and bizarre reference from someone who is seemingly detached from reality.