Nope. It is so of
all speakers,
whatever the design. Note the words I used carefully, please. I mentioned bass flatness, as I recall. One can play around with the rolloff slopes, but then one is altering the bass frequency response.
A reflex design, which rolls off the bass at 18 db per octave rather than 12 db, can have a higher efficiency for the same size box as a sealed design, but at the expense of a steeper rolloff and less ultimate extension. Or it can have a lower -3db point for the same efficiency. You can play around with the slopes, but leaving the rolloff slope the same then the size of the box alters either the allowable efficiency for the same extension, or the bass extension for the same efficiency.
Given two boxes of the same basic design and the same frequency response the larger one will always be more efficient, period, as a consequence of the laws of physics.
Contrawise, given two boxes of the same bass rolloff slopes, and the same size, the more efficient system will have a higher bass cutoff as a consequence of the laws of physics.
Flux density is one of the determining factors of system Q. If all else is held equal, then increasing the flux density will indeed alter Q factor of the fundamental resonance, changing the bass slope and consequently the bass response, higher flux density resulting in a higher bass cutoff.
Get yourself a book on loudspeaker design and look it up for yourself. Or read this link on
Hoffman's Iron Law.
As
wikipedia states "It is not possible to combine high efficiency (especially at low frequencies) with compact enclosure size and adequate low frequency response. One can, more or less, choose only two of the three parameters when designing a speaker system. So, for example, if extended low-frequency performance and small box size are important, one must accept low efficiency.[26] This rule of thumb is sometimes called Hoffman's Iron Law (after J.A. Hoffman, the "H" in KLH).[27]"