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cmb5286
Junior Audioholic
After hearing everything I've decided just to buy some canare 4S11 and terminate them myself with some locking plugs. Thanks for the input
Based on the AH article, the cable's impedance will not influence anything. With interconnects, capacitance will, especially in longer lengths.Braiding is of no importance.
Each pair is 100 ohms. One cable will produce 25 ohms.
4 cables will be 6.25 ohms..
Cut 4 lengths, strip the ends, wire all the stripes together, and all the solids together.
You will have a 6.25 ohm cable.
Give it a try.
No idea if you'll hear anything different though..
Cheers, John
I wouldnt classify the amount of current it takes to drive a set of speakers "high"....LOL!!Ok, I'll come out and say it: Using CAT5 for high current transmission is simply idiotic.
As I stated, ""No idea if you'll hear anything different though.."".Based on the AH article, the cable's impedance will not influence anything. With interconnects, capacitance will, especially in longer lengths.
Each pair is 100 ohms.
Cheers, John
The input and output impedance of the component will have a determining factor on this too. One reason why passive preamps with high output impedance has a marked effect on FR., especially when it varies with volume control settings.With interconnects, capacitance will, especially in longer lengths.
All frequencies between DC and daylight.At audio frequencies? Or, at the RF frequencies cat 5 usually operates?
It is characteristic impedance.Then, how is this different from characteristic impedance? I have seen those curves and it isn't flat from DC to light but a huge S curve or something at low frequencies.