Bill Whitlock writes about common impedance coupling noise:
Leakage Current Effect - A Calculated Example
•A 25-foot cable (foil shield, #26 AWG drain wire) has an end-to-end shield resistance of 1Ω
•Measured leakage current between the ungrounded devices is 316μA (well under the UL limit of 750 μA)
•From Ohm’s law, noise voltage E = I x R = 316 μA x 1Ω= 316 μV
•Consumer−10 dBV reference level = 316 mV
•Signal to Noise ratio = 20 x log (316 mV⁄316 μV) =60 dB
•This is 35 dB worse than an audio CD!
•Same length of Belden #8241F cable, with its shield resistance of only 0.065Ω,
makes S⁄N 84 dB, an improvement of 24 dB!