What would happen if I hooked up a 9V battery to my speakers?

  • Thread starter Thread starter Porcupine
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Porcupine

Audioholic Intern
May 2, 2005
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Honolulu, HI
I am curious...I suspect that bad things would happen since it is DC current. Since I am not willing to try this out experimentally, does anyone know what would happen?

Would the cones just bulge out a little and stay there? Or would they bulge out A LOT to their extremes and really be hurting themselves? I don't think the voice coils would burn up because 9V is still only 10 watts of power or so to an 8 Ohm speaker.

When I refoamed the woofers on a pair of my speakers recently I noticed that woofers inherently have some spring-like resistance to being extended or pushed in, even without the foams on. What generates this resistance? Is it just the spider?

I used to think that the current/voltage signal running through my speakers was proportional to their cone position. Thus, if I looked at a computer WAV-file I would be seeing driver displacement vs time. But now I think the current/voltage signal, and the WAV-files, are actually graphing driver acceleration/force vs time. If that is so, even a tiny DC offset applied by either a 9V battery or a faulty recording source might continually order my speaker cone to "bulge out" until it bursts....

I worry about this because I have played poorly recorded things before that have had moderate DC offsets in the signal. I have never had any problems but I wonder how bad even a tiny DC offset is for a woofer.
 
Why would you want to do that?

A 1.5 volt battery is more than adequate for tracing wire runs of checking the polarity of a speaker
 
A 9V battery will not harm the speaks at all, unless you somehow manage to shove 500 amps thru the wire too. (Highly improbable if not impossible)

Either way, great way to check polarity and make sure you have everything hooked up right.

Paul
 

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