size of regular tv pic on widescreen display

[pbarach]

Does anyone happen to know the diagonal width of a normal broadcast TV signal when displayed on a 34" widescreen display? I don't like the way the "stretched" version of of a broadcast TV signal looks on the widescreen displays. Thanks for your help!

 

[Leprkon]

measure the height of the screen. multiply by 1.33 to get the picture width. then use the pythagorean theorem h^2 = o^2 + a^2 or the hyptenuse (diagonal) squared is equal to the sum of the squares of the two sides.

math on Sunday morning !!

 

[BMXTRIX]

About 28 inches.

Right around the same size as one of the old 27" TVs that are so common in the 4x3 size.

 

[Leprkon]

what he said...

 

[Duffinator]

This will give you the dimensions you seek...

http://www.cavecreations.com/tv2.cgi?KeohiHDTV

 

[pbarach]

thanks!

The link provided in Duffinator's message provided the easiest solution. I was aware that I could calculate the answer to my question using the Pythagorean theorem, but I needed the height of the 34"-diagonal 16:9 set, and I didn't have one available... Thanks to all who responded!

 

[MDS]

measure the height of the screen. multiply by 1.33 to get the picture width. then use the pythagorean theorem h^2 = o^2 + a^2 or the hyptenuse (diagonal) squared is equal to the sum of the squares of the two sides.

math on Sunday morning !!

Isn't it a^2 = b^2 + c^2?.

Do I take h to be hypotenuse, o = opposite and a = adjacent? Reminds me of the silly little acronym we learned in middle school: SOHCAHTOA. It doesn't stand for anything and we just pronounced it 'SO-KA-TOE-UH'. Yet I remember it to this day and it is an easy way to remember sine=opposite over hypotenuse, etc.

 

[Leprkon]

Isn't it a^2 = b^2 + c^2?.

Do I take h to be hypotenuse, o = opposite and a = adjacent? Reminds me of the silly little acronym we learned in middle school: SOHCAHTOA. It doesn't stand for anything and we just pronounced it 'SO-KA-TOE-UH'. Yet I remember it to this day and it is an easy way to remember sine=opposite over hypotenuse, etc.

we always used

Oscar Had (sine)
A Heap (cosine)
Of Apples (tangent)

 

[GeorgeM]

I'm going to pick up my good friend Will Hunting and drive over to M.I.T. to see if the info that you guys have furnished here is valid . We might even solve some unresolved theorems along the way .

-GeorgeM

 

[ebough]

You will find the following explanation more helpful than all of the above: http://www.hdtvoice.com/voice/showthread.php?t=1047