In case you want to know how to calculate the equivalent impedance of more than 2 speakers, the more general forumla is:
1/Zeq=1/Z1+1/Z2+1/Z3+.......+1/Zn (Req=equivalent impedance)
Formula is one thing, but please be reminded that in your example of 16 and 8 in parallel, if the 16 could dip frequently down to 8 and the 8 down to 4, then in the worst case scenario, the amp will see 8 and 4 in parallel, giving an equivalent of 2.66 ohms (see formula in j Garcia's post) if they dip to their minimum at the same time. Not likely but be aware that it could happen.