MacManNM said:
Yes it does. He is speaking of a full wave rectified power supply, I used a half wave unit for my example.
This is correct. What I was wondering, is why in the world is anyone talking about half wave rectification supplies for any type of power amp. It has been known for decades that this significantly increases the eddy losses in the core, the ripple power losses in the caps, and the peak diode junction temperatures. You should have stated up front that your examples were not consistent with currently accepted amplifier design practices..
Comments on the following...note that I did not copy all of the correct postings, but some that are interesting..
MacManNM said:
Incorrect. It is twice the power..10dB is twice as loud.
MacManNM said:
you are speaking of what the ear perceives. Just because your ear is a nonlinear device doesn’t mean that 3db isn’t twice as loud, it is. Please don’t tell me I’m wrong when you are comparing your apples to my oranges. How do you know that he isn’t sitting 70ft away from his speakers and the average SPL at his position is 85dbm, so an increase of 3db would be measured as twice as loud, and perceived as twice as loud. 3db is twice as loud period.
3 dB is indeed measured as twice as much power. But it is not perceived as twice as loud, no matter what the relative distance or level is. It requires 10dB increase of power at any power level, to be perceived as twice as loud.
MacManNM said:
Again, you don't know what the levels are at his listening position, so you can presume what you like. It doesn't matter to me, but 3db is 3db no matter how you slice it.
See the last statement. The relation is intensity independent.
MacManNM said:
If you read the article it basically says that the ear is nonlinear. At higher levels the responsivity changes. It totally depends on the ambient noise and the spl at the listening position. So in reality we are both right, just I'm a little more right. it is all a matter of perspective.
No. it is 10dB, it is not a matter of perspective.
MacManNM said:
The poster said he wants the neighbors to hear his system, since they are in the far field the 3db gain is going to seem much greater to them moreso than to the person sitting in front of the TV.
No. See above.
MacManNM said:
You don't buy it because you don't understand it. The recovery time can't be any faster than 16ms (20 ms if you live across the big pond). Now, if your peak is 60 Hz or lower they won't recover in time.
Incorrect for modern power amps. However, included here for continuity, as the statement half wave has since been introduced.
mtry said:
: I thought that is recitified and DC is fed to the caps, hence, the line frequency is irrelevant.
Incorrect. Line frequency plays a big role in how long the cap has to wait until the transformer voltage starts to exceed the voltage the capacitors were discharged to.
MacManNM said:
No, I am not mistaken, the limiting factor of a WELL designed amp is the input line current,frequency. The things that Dan are talking about happen well after the capacitave reserve runs out, so, the more capacitance you have, the better.
All are tradeoffs. Good amps with small caps are possible as well as large caps. Most designers do not understand well enough e/m field theory to design extremely good amps with small cap banks. A limit to a power amp is of course the input current, as ya can't get more than what the breaker will allow..for long.
MacManNM said:
It is rectified but it is pulsed DC. The caps are what make it line level DC
Correct,
mtry said:
The AC is rectified. Caps charge by DC so there is no crossing, just DC and the RC time constant is in play on charging time.
Incorrect. The caps at the primary supply are fed by rectified sine, with the current occuring near the peak of the voltage wave.
mtry said:
Then, by your logic, if you played a 10kHz sine wave to check the RMS power output, those caps would never recharge and would be depleted in a hurry as you are discharging faster than you can recharge it? .
Incorrect. The cap voltage will decay between charge pulses based on the average current that is drawn from the cap. It will rise up, riding the ac, when the ac exceeds the voltage of the cap at the instant. If there is insufficient power capability for recharging, the cap voltage will start a downward trend, looking like a sawtooth of sorts, until the conduction angle reaches equilibrium where the power input matches the power draw.
An interesting point here. The 10 Khz ripple will be on the supply capacitors, and when the diode conducts to recharge the cap, this ripple voltage will be superimposed on the transformer secondary, and through to the primary, where is will go into the AC power line. Under no circumstances, is this ripple current considered when discussing line cords..given that this is 166 times line frequency, what prevents this from coupling to the input ground loop..remember, the faraday coupling constant is proportional to frequency, if you have hum at a 1 millivolt level, you will have 10K freq at 166 mV..audible..no?
MacManNM said:
One must also remember that the DC line voltage is usualy somewhere around .707 x the rectified peak voltage, usually a little less though. This means it will take a good portion of the waveform to charge them. Also depending on the size of the power supply (size of the caps), it may well take several cycles to charge the caps completely.
As was pointed out, it is 1.414, or 1/.7071.
Cheers, John